For the constraints $0.8 \leq\left|\mathrm{H}\left(\mathrm{e}^{\mathrm{jw}}\right)\right| \leq 1 \quad, 0 \leq \mathrm{w} \leq 0.2 \pi$

$ \left|\mathrm{H}\left(\mathrm{e}^{\mathrm{jw}}\right)\right| \leq 0.2 \quad, 0.6 \pi \leq \mathrm{w} \leq \pi\\ $

With $\mathrm{T}=1$ sec.Determine system function $\mathrm{H}(\mathrm{z})$ for a Butterworth filter using the impulse invariant method.

Solution:

Given $\frac{1}{\sqrt{1+\varepsilon^2}}=0.8$ from which $\varepsilon=0.75$

$\frac{1}{\sqrt{1+\lambda^2}}=0.2$ from which $\lambda=4.899$.

$\omega_s=0.6 \pi \mathrm{rad}, \omega_p=0.2 \pi \mathrm{rad}$

$ \begin{aligned}\\ &\frac{\omega_s}{\omega_p}=\frac{\Omega_s T}{\Omega_p T}=\frac{\Omega_s}{\Omega_p}=\frac{0.6 \pi}{0.2 \pi}=3 \\\\ &\begin{aligned}\\ N=\frac{\log d_{\varepsilon}}{\log 1 / k} &=\frac{\log 4.899}{\log 3} \\\\ &=1.71\\ \end{aligned}\\ \end{aligned}\\ $

$ \begin{aligned}\\ &\therefore N=2\\\\ &H(s)=\frac{1}{s^2+\sqrt{2} s+1}\\\\ &\Omega_c=\frac{\Omega_p}{\varepsilon^{1 / N}}=\frac{0.2 \pi}{(0.75)^{1 / 2}}\\\\ …