Solution:

Bilinear or Tustin Transformation:

To overcome the difficulty of the impulse invariant method, bilinear transformation may be used. Tn this method the entire $j \Omega$ axis for $-\infty\lt\Omega\lt\infty$ maps uniquely onto the unit circle for $-\pi\lt\omega\lt\pi$.

The bilinear transform provides a nonlinear one-to-one mapping of the frequency points on …