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Design first-order low pass fitter using opamp at a cut off frequency of $1 \mathrm{Khz}$, having pass band gain of 2 .
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Solution:

Given; $\quad f_{H 1}=1 \mathrm{KH}_2$ Let, $C=0.01 \mathrm{MF}$

Therefore, R can be obtained as a.

\begin{aligned} &R=\frac{1}{2 \pi \times 10^3 \times 0.01 \times 10^{-6}} \\ &R=15.9 \mathrm{k} \Omega . \end{aligned}\\

A $20 \mathrm{~K} \Omega$ potentiometer can be used to set the resistance R.

since the passing gain is $2, R_1$ and $R_F$ must be equal. Let $R_1=R_2=10 \mathrm{k} Q$