Solution:

Given Data-

$ \begin{aligned} &f_0=2 \mathrm{kH} \\ &v_{p p}=7 \mathrm{~V} \\ &v_{\text {sat }}=\pm \mathrm{14KV} \end{aligned} $

Step 1;-

$ V_{\text {o }}[\text { peak }]=\frac{R_2 \cdot V_2}{R_3}\\ $

Now because the Zener diodes are not being used, replace $V_z$ by $V_{\text {sat }}$ moreover as $V_0[p-p]=$ $2 v_0$ …