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Calculate amount of lime (90% pure) and soda (98% pure)
written 8.6 years ago by gravatar for teamques10 teamques10 ★ 69k •   modified 8.6 years ago

Calculate amount of lime (90% pure) and soda (98% pure) for the treatment of one million litres of water containing $Ca(HCO_3)_2$=8.1 ppm , $CaCl_2$ = 33.3 ppm, $HCO_3$- =91.5 ppm , $MgCl_2$ = 38 ppm , $Mg(HCO_3)_2$ =14.6 ppm .The coagulant $Al_2(So_4)_3$ was added at the rate of 17.1 ppm.

Mumbai University > First Year Engineering > Sem1 > Applied Chemistry 1

Marks: 5M

Year: Dec 12, May 12
engineering chemistry
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written 8.6 years ago by gravatar for teamques10 teamques10 ★ 69k
salt QTY (mg/lit) Mol. Wt Multiplying factor CaCO3 equivalent Requirement L or / and S
$CaCl_2$ 33.3 111 33.3*100/111 30 S
Ca(HCO3)2 8.1 162 8.1*100/162 5 L
$HCO3^-$ 91.5 122 91.5*100/122 75 ADD IN L SUBTRACT IN S
$MgCl_2$ 38 95 38*100/95 40 L+S
Mg(HCO3)2 14.6 146 14.6*100/146 10 2L
Al2(So4)3 17.1 342 17.1*100/342 5 L AND S BOTH

FORMULA-

LIME = 74/100 (5+75+40+2*10+5) * (1million/106) * (100/90[purity of water])

= 119.2 kg

SODA= 106/100(30+40+5-75)1100/98

= 0 kg
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