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What is the total hardness of sample of water containing following impurities in $mg/lCa(HCO3)2=162$ , CaCl2=22.2 , NaCl=20 , $MgCl_2=95$
written 7.9 years ago by gravatar for teamques10 teamques10 ★ 65k •   modified 7.9 years ago

Mumbai University > First Year Engineering > Sem1 > Applied Chemistry 1

Marks: 3M

Year: May 13, Dec13, Dec 122
engineering chemistry
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written 7.9 years ago by gravatar for teamques10 teamques10 ★ 65k
Impurities Quantity Mg/lit Multiplying factor CaCO3 equivalents in ppm
Ca(HCO3)2 162 162*100/162 100
CaCl2 22.2 22.2*100/111 20
NaCl 20 0 Not counted
MgCl2 95 95*100/95 100

Temporary hardness= Ca(HCO3)2=100ppm

Permanent hardness= CaCl2 + MgCl2 = 120 ppm

∴ Total hardness= 100+120= 220 ppm

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