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Solve $x-2 \sin x-3=0$ correct to two significant figures by Newton Raphson method correct up to 5 significant digits.
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written 3.0 years ago by
prajapatijaimin
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Solution:
Let $f(x)=x-2 \sin x-3$
$ \begin{aligned}\\ & f(0)=-3, f(1)=-2-2 \sin 1, f(2)=-1-2 \sin 2, f(3)=-2 \sin 3, f(4)=1-2 \sin 4 \\\\ & f(-2)=-5+2 \sin 2 \quad, f(-1)=-4+2 \sin 1\\ \end{aligned}\\ $
As $f(3) f(4)\lt0$ by Intermediate value Theorem the root of the real root of the equation $f(x)=0$ lies …
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