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Find the output y(n) of a filter whose impulse response is h(n)=(1,1,1) and input signal x(n)=(3,-1,0,1,3,2,0,1,2,1) using over lab save method.
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Solution:

Overlap save method:

$ \begin{aligned} & \mathrm{x}_1(\mathrm{n})=\{0,0,3,-1,0\} \\\\ & \mathrm{M}-1=2 \text { zeros } \mathrm{L}=3 \text { data points } \\\\ & \mathrm{x}_2(\mathrm{n})=\{-1,0,1,3,2\}\\ \end{aligned} $

2 data from previous 3 new data $x_3(n)=\{3,2,0,1,2\}$ and $x_4(n)=\{1,2,1,0,0\}$

Given $\mathrm{h}(\mathrm{n})=\{1,1,1\}$

Increase the length by adding zeros( L+M-1=5)

i.e. $h(n)=\{1,1,1,0,0\}$

$\left[\begin{array}{lllll}1 & 0 …

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