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Determine if the following systems are time-invariant or time-variant. (i) $y(n)=x(n)+x(n-1)$ (ii) $y(n)=x(-n)$
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written 17 months ago by
prajapatijaimin
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Solution:
(i) $y(n)=x(n)+x(n-1)$
Given:
output of the system $y(n)=x(n)+x(n-1)$
If the input is delayed by ' $\mathrm{k}$ ' units in time, we have
$ y(n, k)=x(n-k)+x(n-k-1) $
If the output is delayed by ' k ' units in time, then $(n-\gtn-k)$
$ y(n-k)=x(n-k)+x(n-k-1) $
Here, $y(n, k)=y(n-k)$
Therefore, the system …
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