Divide 24 into 3 parts such that the product of the first, square of second and cube of the third is maximum.

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Divide 24 into 3 parts such that the product of the first, square of second and cube of the third is maximum.

written 7.9 years ago by

teamques10 ★ 65k

modified 2.3 years ago by

pedsangini276 • 4.8k

Mumbai University > First Year Engineering > Sem 1 > Applied Maths 1

Marks : 6 M

Year : May 2014

engineering mathematics

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4.9kviews

written 7.9 years ago by

teamques10 ★ 65k

Let $ x$ and $ y$ be two natural numbers. Let $ z$ be the third number such that $ x +y+z=24$ and $ z=24-x-y$

Let $ u$ be the function of $ x$ and $ y$ such that the product of the first, square of second and cube of …

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