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Walsh transform is nothing but sequency ordered Hadamard transform matrix. Justify.
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The above statement is false.

The sequencyHadamard transform matrix for N=4 is given by,

$H = \frac{1}{\sqrt{4}} \begin{bmatrix} \ 1 & 1 & 1 & 1 \\ \ 1 & 1 & -1 & -1 \\ \ 1 & -1 & -1 & 1 \\ \ 1 & -1 & 1 & -1 \\ \end{bmatrix}$

The 2D matrix representation of Walsh transform can be given as,

$W = \frac{1}{\sqrt{4}} \begin{bmatrix} \ 1 & 1 & 1 & 1 \\ \ 1 & 1 & -1 & 1 \\ \ 1 & -1 & 1 & -1 \\ \ 1 & 1 & -1 & 1 \\ \end{bmatrix}$

NOTE: Walsh Transform is removed in the revised syllabus but since the question is related to Hadamard Transform it may be asked.

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