**1 Answer**

0

1.5kviews

Walsh transform is nothing but sequency ordered Hadamard transform matrix. Justify.

0

2views

written 5.3 years ago by |

The above statement is false.

The sequencyHadamard transform matrix for N=4 is given by,

$H = \frac{1}{\sqrt{4}} \begin{bmatrix} \ 1 & 1 & 1 & 1 \\ \ 1 & 1 & -1 & -1 \\ \ 1 & -1 & -1 & 1 \\ \ 1 & -1 & 1 & -1 \\ \end{bmatrix}$

The 2D matrix representation of Walsh transform can be given as,

$W = \frac{1}{\sqrt{4}} \begin{bmatrix} \ 1 & 1 & 1 & 1 \\ \ 1 & 1 & -1 & 1 \\ \ 1 & -1 & 1 & -1 \\ \ 1 & 1 & -1 & 1 \\ \end{bmatrix}$

**NOTE:** Walsh Transform is removed in the revised syllabus but since the question is related to Hadamard Transform it may be asked.

ADD COMMENT
EDIT

Please log in to add an answer.