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A tee beam consists of a flange $1100$ mm wide $120$ mm deep the depth of the beam is $600$ mm upto the centre of steel and width of web $300$ mm.
written 7.9 years ago by gravatar for teamques10 teamques10 ★ 65k •   modified 3.4 years ago

Find the area of steel required for an ultimate moment of $600KNm.$ Use $M20/F_{e415}$ .
reinforced concrete structures theory
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written 7.9 years ago by gravatar for teamques10 teamques10 ★ 65k •   modified 7.9 years ago

Data: $b_f =1100 mm \\ D_f =120mm \\ b_w =300mm \\ d = 600 mm \\ M_d =600KN/m \\ f_ck = 20N/mm^2 \\ f_y =415 N/mm^2 $

Assume, $X_u =D_f =120$ mm

$M_uf=C_u\times L_a \\ M_uf=0.36f_ckb_fX_u\times (d-0.42X_u)\\ M_uf=0.36\times20\times 1100\times 120\times (600-0.42\times 120)\\ M_uf=522.33KNm\\ \therefore M_d \gt M_uf \hspace {1cm} \text …

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