written 5.1 years ago by | modified 7 months ago by |

Width of flange = $800$ mm

Depth of slab = $80$ mm

Width of rub = $300$ mm

Area of steel = $4-20$ mm on tension side

D = $450$ mm, dc = $50$ mm

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Find the ultimate moment of resistance of T beam section using $F_{e415}$ steel grade and M20 concrete grade.

written 5.1 years ago by | modified 7 months ago by |

Width of flange = $800$ mm

Depth of slab = $80$ mm

Width of rub = $300$ mm

Area of steel = $4-20$ mm on tension side

D = $450$ mm, dc = $50$ mm

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written 5.1 years ago by |

Data:- $b_f =800 mm \\ D_f = 80 mm \\ b_w =300 mm \\ d = 450 mm \\ Ast = 4-20 mm \\ =1256.63 mm^2\\ M20, F_{e415}$

Assume $X_u \lt D_f$ [N.A lies in the flange]

$C_u=T_u\\ 0.36f_ckb_fX_u=0.87f_yAst\\ 0.36\times 20\times800\times X_u=0.87\times415\times1256.63 \\ X_u=78.76mm \lt D_f $

Assumption is correct

Now $X_{u\space max}=0.48d=0.48\times 450=216mm\\ X_u \lt X_{u\space max} ... \text{ Hence under reinforced section. }\\ M_u=(C_{u1}\times L_{a1})\\ M_u=[(0.36f_ckb_wX_{u\space max})\times (d-0.42 X_{u\space max})]\\ M_u =0.36\times20\times800\times78.76\times(4550-0.42\times78.76) \\ M_u=189.13 KNm$

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