Design the shear reinforcement for the rectangular beam of dimensions $300 \times 50$ mm (effective) provided with $4 -20$mm in tension zone. beam is subjected to a udl of $50$KN/m having span $4m.$

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written 9.4 years ago by

teamques10 ★ 70k

modified 3.5 years ago by

sagarkolekar ★ 11k

Use M20 concrete and $F_{e415}$ steel. Refer table from paper of Zuc values Adopt LSM

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written 9.4 years ago by

teamques10 ★ 70k

$$b= 300 mm \ d=500mm\ d_c=50mm \ l=4m\ Ast=4-20mm\space \phi=1256mm^2\ D=550 mm \ self \space wt=(0.3\times 0.55)\times25=4.125kn/m$$

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factored shear force $(V_{UD} )= 1.5 \times v \\ = 1.5 \times 81.18 \\ = 121.78 KN \\ Z_{uv}=\dfrac {V_{UD}}{b\times d}=\dfrac {121.78\times10^3}{300\times500}=0.81 N/mm^2 \lt 2.8 N/mm^2 \therefore safe\\ pt=\dfrac {100Ast}{b\times d}=\dfrac {100\times1256}{300\times500}= 0.83\%$ …

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