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Show that:Highpass = Original-Lowpass
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written 8.3 years ago by
teamques10
★ 67k
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When we apply the LPF on the image, the center pixel z5 changes to
$1/9[z_1+z_2+z_3+z_4+z_5+z_6+z_7+z_8+z_9]$
Original- Low pass $=z_5 - 1/9[z_1+z_2+z_3+z_4+z_5+z_6+z_7+z_8+z_9] \\ = z_5 - 1/9[z_1+z_2+z_3+z_4+z_5+z_6+z_7+z_8+z_9] \\ =8/9 z_5-1/9z_1-1/9z_2-1/9z_3-1/9z_4-1/9z_6-1/9z_7-1/9z_8-1/9z_9 \\ =1/9Χ \ high \ pass \ mask$
| -1 | -1 | -1 |
|---|---|---|
| -1 | 8 | -1 |
| -1 | -1 | -1 |
This is nothing but …
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