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For the 3-bit 4x4 size image perform the following operation.

(1)Thresholding with T=4

(2)Intensity level slicing with background r1=2 and r2=5

(3)Bit plane slicing for MSB and LSB plane

(4) Negation

4 2 3 0
1 3 5 7
5 3 2 1
2 4 6 7
1 Answer
2
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(i) Thresholding

Since the image is 3 bit,L=23=8

For Thresholding

$S = \begin{cases} L-1, & r \ge T \\ 0, & \text{otherwse} \end{cases}$

Here,L-1=7,T=4

7 0 0 0
0 0 7 7
7 0 0 0
0 7 7 7

(ii) Intensity level slicing with background r1=2 and r2=5:

$S = \begin{cases} L-1, & r1 \gt r \gt r2 \\ r, & \text{otherwse} \end{cases}$

Here,L-1 = 7 , 2 ≤ r ≤ 5

7 7 7 0
1 7 7 7
7 7 7 1
7 7 6 7

(iii) Bit plane slicing for MSB and LSB plane:

We convert the original image into a 3-bit binary image

100 010 011 000
001 011 101 111
101 011 010 001
010 100 110 111

We create three planes from the bit positions

1 0 0 0
0 0 1 1
1 0 0 0
0 1 1 1

MSB plane

0 1 1 0
0 1 0 1
0 1 1 0
0 0 1 1
0 0 1 0
1 1 1 1
1 1 0 1
0 0 0 1

LSB plane

(iv) Negation:

Image negative is given by the formula

S=(L-1)- r

Therefore,s=7-r

3 5 4 7
6 4 2 0
2 4 5 6
5 3 1 0
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