(1)Thresholding with T=4

(2)Intensity level slicing with background r1=2 and r2=5

(3)Bit plane slicing for MSB and LSB plane

(4) Negation

(i) Thresholding

Since the image is 3 bit,L=23=8

For Thresholding

$S = \begin{cases} L-1, & r \ge T \\ 0, & \text{otherwse} \end{cases}$

Here,L-1=7,T=4

(ii) Intensity level slicing with background r1=2 and r2=5:

$S = \begin{cases} L-1, & r1 \gt r \gt r2 \\ r, & \text{otherwse} \end{cases}$

Here,L-1 = 7 , 2 ≤ r ≤ 5

(iii) Bit plane slicing for MSB and LSB plane:

We convert the original image into a 3-bit binary image

We create three planes from the bit positions

MSB plane

LSB plane

(iv) Negation:

Image negative is given by the formula

S=(L-1)- r

Therefore,s=7-r