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Design a short axially loaded square column to carry an axial load of $2250 kN.$ Use M20 concrete and $Fe415$ steel. Adopt reinforcement details.
written 9.4 years ago by gravatar for teamques10 teamques10 ★ 70k modified 3.5 years ago by gravatar for jyothisai112 jyothisai112 • 10
reinforced concrete structures theory
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written 9.4 years ago by gravatar for teamques10 teamques10 ★ 70k

$$P=2250 kN\space\space M20\space \&\space Fe415$$

$P_u=1.5×2250=3375 kN \\ \text { Assume 1% steel of gross c/s }\\ \text {99% concrete of gross c/s }\\ Asc =0.01 A_g\\ Ac = 0.99 A_g \\ Now \space P_{uc}=0.4 f_{ck} A_c+0.67 f_y A_{sc} \\ 3375 ×10^3=[0.4 ×20×0.99 A_g+0.67 ×415×0.01 A_g] \\ A_g=315405.82 mm^2 \\ …

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