Design the footing for the column assuming safe bearing capacity of the soil to the $210KN/m^2$ . Use M25 & TOR steel.

Column size $(275 \times 450) mm \\ P = 900KN \\ Pu = 1.5 \times 900 = 1350 KN \\ SBC = 210 KN/m^2$

Area of footing $(A_f)=\dfrac {P+10 \% \text {extra assel fwt.}}{SBC}\\ =\dfrac {900+\frac {10}{100}\times 900}{210}\\ =A_f=4.71m^2$

$$C_x=\dfrac {B-0.275}2 ; C_y=\dfrac {L-0.45}2$$

$Now, C_x=C_y\\ \dfrac {B-0.275}2 =\dfrac {L-0.45}2 …