| written 9.8 years ago by | • modified 9.8 years ago |
Mumbai University > COMPS > Sem 4 > Applied Mathematics 4
Marks : 06
Year : MAY 2014
| written 9.8 years ago by | • modified 9.8 years ago |
Mumbai University > COMPS > Sem 4 > Applied Mathematics 4
Marks : 06
Year : MAY 2014
| written 9.8 years ago by |
Since A is a upper triangular matrix, Eigen value (x)= diagonal element= $2,2,2$
Case 1: Let $f(x)=(x-2)\\ \therefore f(A)=A-2I$
$$A= \begin{bmatrix} 2 & 1 & 0 \\ 0 & 2 & 1 \\ 0 & 0 & 2 \\ \end{bmatrix}-2\begin{bmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \\ \end{bmatrix}$$
$$=\begin{bmatrix} 0 & 1 & 0 \\ 0 & 0 & 1 \\ 0 & 0 & 0 \\ \end{bmatrix}\neq 0$$
$\therefore f(x)=x-2$ does not annihilates A
So, f(x) in not a minimal polynomial
Case 2: Let $g(x)=(x-2)(x-2)=x^2-4x+4$
Now $A^2=A\times A$
$$=\begin{bmatrix} 2 & 1 & 0 \\ 0 & 2 & 1 \\ 0 & 0 & 2 \\ \end{bmatrix}\times \begin{bmatrix} 2 & 1 & 0 \\ 0 & 2 & 1 \\ 0 & 0 & 2 \\ \end{bmatrix}$$
$$=\begin{bmatrix} 4 & 4 & 0 \\ 0 & 4 & 4 \\ 0 & 0 & 4 \\ \end{bmatrix}$$
$$\therefore A^2-4A+4I$$
$$\begin{bmatrix} 4 & 4 & 0 \\ 0 & 4 & 4 \\ 0 & 0 & 4 \\ \end{bmatrix}-4\begin{bmatrix} 2 & 1 & 0 \\ 0 & 2 & 1 \\ 0 & 0 & 2 \\ \end{bmatrix}+4\begin{bmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \\ \end{bmatrix}$$
$$\begin{bmatrix} 0 & 0 & 1 \\ 0 & 0 & 0 \\ 0 & 0 & 0 \\ \end{bmatrix}\neq 0$$
$\therefore g(x)=x^2-4x+4$ does not annihilates A
So, g(x) is not a minimal polynomial
Here, matrix A is not derogatory