Mumbai University > Computer Engineering > Sem4 > Computer Organization and Architecture

Marks: 7M

Year: May 14

Using the flowchart, we can solve the given question as follows:

$(5)_{10}= 0101$ (in 2’s complement)

$(7)_{10} =0111$ (in 2’s complement)

Multiplicand (B) = 0101

Multiplier (Q) = 0111

And initially $Q_{-1}$= 0

Count =4

Steps	A	Q	$Q_1$	Operation
Initial	0000	0111	0	-
1	1011 1101	0111 1011 …