Derive an expression for the elongation due to self-weight of a bar.

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written 9.4 years ago by

teamques10 ★ 70k

Consider a bar of circular cross section and uniform diameter throughout. Consider it to be suspended from a rigid support and its top end, such that it is in a hanging in a vertical position as shown in the figure.

Let,

A = Uniform cross sectional area of the bar …

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ADD COMMENT EDIT

Make me understand from here Change in the length of the element ‘dy’ = PlAE=ρ×(A×y)×dyAEPlAE=ρ×(A×y)×dyAE

=ρ×y×dyE

8.3 years ago by teamques10 ★ 70k