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Derive an expression for the elongation due to self-weight of a bar.
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Consider a bar of circular cross section and uniform diameter throughout. Consider it to be suspended from a rigid support and its top end, such that it is in a hanging in a vertical position as shown in the figure.

enter image description here

Let,

A = Uniform cross sectional area of the bar …

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Make me understand from here Change in the length of the element ‘dy’ = PlAE=ρ×(A×y)×dyAEPlAE=ρ×(A×y)×dyAE

=ρ×y×dyE


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