Mumbai University > COMPS > Sem 4 > Applied Mathematics 4

Marks : 06

Year : DEC 2015

Let us answer 75 and 55 be the mean of x and y respectively.

$r=\dfrac {\sum dxdy-\frac {\sum dx\sum dy}N} {\sqrt{\sum dx^2-\frac {(\sum dx)^2}N}\sqrt{\sum dy^2- \frac {(\sum dy)^2}N}}\\ r=\dfrac {-6305-\frac {(-264)(-84)}{12}}{\sqrt{14728-\frac {(-264)^2}{12}}\sqrt{8138-\frac {(-84)^2}{12}}}\\ r=\dfrac {-8153}{\sqrt{8920}\sqrt{7550}}=-0.9934$