Step 1:
Null Hypothesis $(H_0):$ Accidents are uniformly distributed during 10 months period
Alternative Hypothesis $(H_a) =$ Accidents are not uniformly distributed during 10 months period.
Step 2: Test statistic
Total accidents $= 120$
If equally distributed, expected accidents per day $= 120/10 = 12$
Since frequency for 4th and 5th months is less than 10 we combine them.
Similarly, frequency for 7th and 8th month is less than 10, so we combine them.
Step 3: LOS = 5%
Degree of freedom $= n – 1 – 2 = 10 – 3 = 7$
Critical value $(x_x^2) = 14.0671$

$x_{cal}^2=\sum \dfrac {(O-E)^2}E=19.9167$
Step 4: Decision
Since $x_{cal}^2 \gt x_x^2, H_0$ is rejected
Accidents are not uniformly distributed during 10 months period.