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Using Norton's theorem, calculate the current through 15 $\Omega$ resistance.

written 9.4 years ago by teamques10 ★ 70k

•   modified 5.6 years ago

basic electrical engineering

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written 9.4 years ago by teamques10 ★ 70k

→In

Current equation

I1 – I2 = 4

Voltage eqn.

30 – 4I1 – 6I2 = 0

4I1 + 6I2 = 30

Solving 1 & 2 simultaneously

I1 = 5.4A

I2= 1.4 A

IN= I2 = 1.4A

RN= 10 Ω

IL= 1.4 * 10/10+ 15 = 0.56A

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