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Find value of current flowing through $5\Omega$ resistance using superposition Theorem.
written 9.5 years ago by gravatar for teamques10 teamques10 ★ 70k •   modified 5.7 years ago

basic electrical engineering
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written 9.5 years ago by gravatar for teamques10 teamques10 ★ 70k

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→ considering 5A current source

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By current Division Rule.

$I15Ω=\dfrac{5(13.6522)}{(5+13.6522)}=3.6597(↓)$

→ considering 10V supply

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$I115Ω=\dfrac{10}{(5+2+6+5.6522)}=0.5361A(↑)$

→ considering 2A current source

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Mesh I

(5+6+10+2)I1-10I2=0

23 I1-10I2=0………… (I)

Mesh II

-10 I1+ (6+3+4+10) I2+12=0

-10I1+23 I2=-12………… (II)

From (I) & (II)

$I2=-0.6433A \hspace{3cm} I1=-0.2797A \\ \ \ \ \ =0.6433A (↓) \hspace{3.2cm} =0.2797(↓)$

Source Current
5A source I15Ω=3.6597 A(↓)
10 V source I115Ω=0.5361 A(↑)
2 A source I1115Ω=0.2771(↓)

$\boxed{I5Ω=3.4033A}$
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