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Convert the star circuit into its equivalent delta circuit.

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Star to delta connection

$R_{AC}=2+6+\dfrac{2\times6}{4}=11 \Omega \\ R_{BC}=4+6+\dfrac{4\times6}{2}=22 \Omega \\ R_{AB}=4+2+\dfrac{4\times2}{6}=7.333\Omega$

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