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For the given circuit find the Norton equivalent between A and B.
written 9.5 years ago by gravatar for teamques10 teamques10 ★ 70k •   modified 5.7 years ago

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basic electrical engineering
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written 9.5 years ago by gravatar for teamques10 teamques10 ★ 70k

Calculation of IN

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$\dfrac{V_x+10}{1}+\dfrac{V_x}{1}+\dfrac{V_x}{1}=0 \\ V_x=\dfrac{10}{3}volts=3.3333V \\ I_N=\dfrac{V_x}{1}=3.3333A(A to B)$

→ Calculation of RN:

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RTH= (1-1+1-1)-1

=1.5Ω

→ Norton’s equivalent circuit:-

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