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Using source transformation find the current flowing through the $8 \Omega$ resistance.
written 9.4 years ago by gravatar for teamques10 teamques10 ★ 70k •   modified 5.6 years ago

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basic electrical engineering
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written 9.4 years ago by gravatar for teamques10 teamques10 ★ 70k

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6Ω || 6Ω=3Ω

Convert 3A current source in parallel with 3Ω resistance into a voltage source in series with 3Ω.

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$$I8Ω=\dfrac{27}{18}=1.5A(↓)$$
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