Three impedances are connected in parallel across 60 sin (wt) voltage source V1, Z1 = 500 rms, Z2= j400 rms and Z3= -j800 rms. Find current in each impedances show that total current = voltage admittance, Also draw phase diagram. -

$Current = \\ Vs = 60 \lt 0^o \\ Z1= 50 \lt 0^o Ω \\ ∴ I1 = Vs/Z1 = 60 \lt 0^o/ 50 \lt 0^o = 1.2 \lt 0^o A \\ Vs= 60 \lt 0^o \\ Z2 = 40 \lt 90^o Ω (0 +j40) \\ ∴ I2= 60 \lt …