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For a series RLC circuit having R=$10\Omega$, L=0.001H and C=$100\mu$. Find the resonant frequency, quality factor and bond width.
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| written 9.5 years ago by |
R=10Ω, L=0.001H and C=100μF
$F_0=\dfrac{1}{2\pi\sqrt{LC}} \\ =\dfrac{1}{2\pi\sqrt{0.01\times100\times\times10^{-6}}} \\ =159.154 Hz \\ Q=\dfrac1R\sqrt{\dfrac LC} \\ =\dfrac{1}{10}\sqrt{\dfrac{0.01}{100\times10^{-6}}} \\ =1 \\ B.W.=\dfrac{R}{2\pi L} \\ =\dfrac{10}{2 \pi 0.01} \\ =159.154 Hz$