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A ladder of 4 m length weighing 200 N is placed as shown in fig . $\mu_B=0.25$ & $\mu_A =0.35$ Calculate the minimum horizontal force to be applied at A to prevent slipping
written 7.8 years ago by gravatar for teamques10 teamques10 ★ 65k •   modified 4.0 years ago

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engineering mechanics
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written 7.8 years ago by gravatar for teamques10 teamques10 ★ 65k •   modified 7.8 years ago

Angle of plane, $θ = \tan^{-1}(4/12) = 18.4$

Solution:

FBD of the ladder can be drawn as follows

enter image description here

$∑ Fx = 0 \\ P + 0.35 Na – Nb = 0 … i \\ ∑Fy = 0 \\ -200 – 600 + Na + 0.25Nb = 0 \\ Na + …

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